The sum of three numbers is 62 . The first number is 10 more than the second. The third number is 2 times the first. What are the numbers? x = the second number
x + 10 = the first number 2(x + 10) = the third number x + x + 10 + 2(x + 10) = 62 {sum of the three numbers is 62} x + x + 10 + 2x + 20 = 62 {used distributive property} 4x + 30 = 62 {combined like terms} 4x = 32 {subtracted 30 from each side} x = 8 {divided each side by 4} x + 10 = 18 {substituted 8, in for x, into x + 10} 2(x + 10) = 36 {substituted 8, in for x, into 2(x + 10)} first number is 18 second number is 8 third number is 36  Algebra House
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